So... Who likes math?

[lagged]

im not very good at math but i am a compsci major so looking at variables is very familiar to me.

heres something that bothered me right away:

a^2 = a*b

a^2 couldnt equal a*b unless:

int *b = &a;

:icon_razz

 

[mkiiSupraMan18]

Can someone get me the exact number of Pi?

 

[OneJoeZee]

im not very good at math but i am a compsci major so looking at variables is very familiar to me.

heres something that bothered me right away:

a^2 = a*b

a^2 couldnt equal a*b unless:

int *b = &a;

:icon_razz

Yes it can. a=b is given. so a squared (a^2) can also be written as a*a. Same thing. We know a=b so a*b=a*a. Same thing. Nothing wrong there.

 

[OneJoeZee]

Did I say 0/0 in my last post?? No I said "nothing"! If I have nothing how can I do anything with it? There IS a difference in the wording so DO NOT put words into my mouth and take the time to READ and COMPREHEND what I type.

Anyways I'm done with this thread.

Use your your brain and not a calculator or computer...

If I start out with nothing... and I try to add nothing to it, divide it by nothing, multiply it with nothing or subtract nothing from it... what is my end result?

Oh damn... nothing.

How is nothing divided by nothing resulting in nothing not the same thing as 0/0 = 0?

You can subtract, add, and multiply by zero all you want but cannot divide. As has been said at least 10 times already.

 

[lagged]

anything divided by zero does not equal zero, nor "nothing"

it has no result because the operation is not possible.

you cant even say the result of something divided by zero is anything because the operation couldnt have taken place to begin with.

 

[lagged]

Yes it can. a=b is given. so a squared (a^2) can also be written as a*a. Same thing. We know a=b so a*b=a*a. Same thing. Nothing wrong there.

what i posted was a lame attempt at programming humor.

 

[HIDPLANET]

 

[ret]

 

[Junior]

line 3.

it's a proof, forget the equals, do it left side right side.

line 2. LS
a^2-b^2

line 3. RS
(a+b)(a-b)

Simplify this, let both a and b = x we get
(2x)(x-x)
(2x)(0)
(0)

so on line 4 where it goes to (a+b) [ or (2x) as we've now got it] that's not a valid simplification, what you've got here is 0 = 0 (the same thing happens on the other side, you can figure that one out yourself tho)

so really your proof comes down to 0/0, which is actually true.

 

[Quin]

lol

 

[ValgeKotkas]

You have one apple. How could you possibly divide it by zero apples?

 

[Big Wang Bandit]

You have one apple. How could you possibly divide it by zero apples?

Eat it

 

[OneJoeZee]

You guys that are telling me that step 3 is 0=0 are missing the point. I know that. Not sure why it keeps being brought up.

The problem was what the proof does from step 3 to step 4 and that is a division by zero to get rid of (a-b). That's it.

 

[ValgeKotkas]

Eat it

Wish me good appetite:icon_bigg

 

[Junior]

I said that it came down to dividing by 0!

 

[annoyingrob]

Way to go Joe, look what you've started.

People in the future will look back at WWIII, started by two opposing sides, arguing the answer to 0/0......

 

[OneJoeZee]

:biglaugh: