Im having some trouble understanding the bearing system again... Need some help. I will use an example here. Say i have a #1 main bore in my block (2.5206") and a #1 Crank journal for that main (2.3622"). That would mean i would need a #2 bearing (.0784" Thickness) correct?
Well in order to figure oil clearance, i would need to do this equation.. B=Block main bore, C= crank main journal, Bear= bearing size (thickness)
B-Bear= (C+.0012" to .0019" oil clearance)
2.5206"-.0784"= 2.4422"
2.4422"-2.3622"= .080" Now why in hell would i want .080" oil clearance?
Please someone help me out...i feel like im doing something wrong here...
http://www.cygnusx1.net/Supra/Library/TSRM/MK3/manual.aspx?S=EM&P=73
Theres the chart with the bearing numbers, crank numbers, block numbers and measurements.
If my C and B are the sizes mentioned above (both #1), with a .0018" oil clearance, my bearing center wall thickness would need to be .1566" according to my calculations, which is not an offered size
Edit: I think my errors are because we are dealing with a circle, which means certain numbers will need to be doubled or divided by two etc... now im just all confused..