Little help with Hw again. Just needs checking.

fonz87

89 Turbo!!!!
Nov 17, 2007
642
0
16
37
Streamwood, IL
Exercise 1: (Binomial distribution) Use Table C

“A university that is better known for its basketball program than for its academic strength claims that 80% of its basketball players get degrees. An investigation examines the fate of all 20 players who entered the program over a period of several years that ended 6 years ago. Of these players, 11 graduated and the remaining 9 are no longer in school. If the university’s claim is true, the number of players who graduate among the 20 studied should have the B(20,0.8) distribution.

(a) Find the probability that exactly 11 of the 20 players graduate.

(b) Find the probability that 11 or fewer players graduate. This probability is so small that it casts doubts on the university’s claim.”

(Hint: In both questions, 11 graduating is the same as 9 failing when looking at 20 students. Failures have the B(20,0.2) distribution which is available in Table C).

Exercise 2:

A quiz has 25 multiple choice questions. Each question has 5 possible answers, one of which is correct. A correct answer is worth 4 points but a point is taken off for each wrong answer. Fill in the blanks below:

The score will be like the sum of_____________draws

from the box: |______________|.

Fill in the first blank with a number and the second with a box of tickets.

Explain your answers.

Exercise 3:

A student organization is planning to ask a sample of 50 students if they have noticed alcohol abuse brochures on campus. The sample percentage who say “Yes” will be reported. The organization’s statistical advisor says that the standard deviation of this percentage will be about 7%.

(a) What would the standard error be if the sample contained 100 students rather than 50?

(b) How large a sample is required to reduce the standard error of the percentage who say “Yes” from 7% to 3.5%? Explain to someone who knows no statistics the advantage of taking a larger sample in a survey of opinions.

Exercise 4: (#1 p.391)

The Residential Energy Consumption Survey found in 1990 that 14.8% of American households had a computer. A market survey organization repeated this study in a certain town with 25,000 households, using a simple random sample of 500 household: 79 of the sample households had computers.


(a) The percentage of households in the town with computers is estimated as:____________;

(b) this estimate is likely to be off by ___________ or so (this is the SE%).



Answers are on the bottom ... just needs checking thats all.... if there correct or not... thanks
 

fonz87

89 Turbo!!!!
Nov 17, 2007
642
0
16
37
Streamwood, IL
Question 1

Since 11 graduating is the same as 9 failing, I looked of Table C for the 9 people failing. Since there are a total of 20 students the ones that failed are 9/20 = .45%. When you look at Table C under 20 and .45% and probability of 11 players graduating = .1771 probability.

For this problem I looked at the nine people who had failed again. I got the probability of nine or less people failing out of 20. Then I subtracted it from 100% which came out that there is 41% probability that 11 or fewer players graduate.


question 2

There are a total of 25 questions with each having five possible options. That makes the total sum of draws 25 * 5=125. Since there is only one right answer in each question there are a total of 25 right answers which I show as 25 (1) and there are a total of 100 wrong answers which I show in the box as 100(0) indicating there are 100 wrong answers.

question 3

Since the standard error is 7% with 50 students then with 100 students the standard error will be cut into half at 3.5%.

A sample of 100 people will be needed to drop the standard error from 7% to 3.5%. The advantage of taking a larger sample in a survey of opinions is that your results will be more accurate. The reason is if you ask 10 people the same question the results will vary and you will not be able to come up with a complete conclusion. If you ask the same question to 100 people the results will be much more accurate and a pattern would start to develop.

question 4

79/500 = 0.158


Sqr(500) * Sqr ((0.158) * (1-0.158)) =
Sqr (500) * (0.158 * 0.842) =
Sqr(500) * Sqr (0.133036) =
8.15